What are the solutions to the equation 2(-(y+9)/2)(-9-(-(y+9)/2)-2y)=0 ?

The solutions to the equation 2(-(y+9)/2)(-9-(-(y+9)/2)-2y)=0 are y=-9,y=-3

Find the zeros of 2(-(y+9)/2)(-9-(-(y+9)/2)-2y)=0

The zeros of 2(-(y+9)/2)(-9-(-(y+9)/2)-2y)=0 are y=-9,y=-3

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2 (- \frac{y + 9}{2}) (- 9 - (- \frac{y + 9}{2}) - 2 y) = 0

y = - 9, y = - 3

Solution steps

2 (- \frac{y + 9}{2}) (- 9 - (- \frac{y + 9}{2}) - 2 y) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

- \frac{y + 9}{2} = 0 or - 9 - (- \frac{y + 9}{2}) - 2 y = 0

Solve

- \frac{y + 9}{2} = 0 : y = - 9

Solve

- 9 - (- \frac{y + 9}{2}) - 2 y = 0 : y = - 3

The solutions to the quadratic equation are:

y = - 9, y = - 3

2 x^{2} - 13 x + 27 = 0

\frac{7}{3} x - \frac{1}{5} = \frac{2}{7} - \frac{11}{2} x

π 5^{2}

x^{2} - 60 x + 900 = 0

7 x^{2} = 3

What are the solutions to the equation 2(-(y+9)/2)(-9-(-(y+9)/2)-2y)=0 ?
The solutions to the equation 2(-(y+9)/2)(-9-(-(y+9)/2)-2y)=0 are y=-9,y=-3
Find the zeros of 2(-(y+9)/2)(-9-(-(y+9)/2)-2y)=0
The zeros of 2(-(y+9)/2)(-9-(-(y+9)/2)-2y)=0 are y=-9,y=-3