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Popular >

2|x-4|-7<= 1

Solution

2 ∣ x - 4 ∣ - 7 \leq 1

Solution

0 \leq x \leq 8

+1

Interval Notation

[0, 8]

Solution steps

2 ∣ x - 4 ∣ - 7 \leq 1

Move

7

to the right side

2 ∣ x - 4 ∣ \leq 8

Divide both sides by

2

∣ x - 4 ∣ \leq 4

Apply absolute rule: If

∣ u ∣ \leq a, a > 0

then

- a \leq u \leq a

- 4 \leq x - 4 \leq 4

x - 4 \geq - 4 and x - 4 \leq 4

x \geq 0 and x \leq 8

Merge Overlapping Intervals

0 \leq x \leq 8

Popular Examples

factor 3x^3-27x factor

3 x^{3} - 27 x

- 4 \leq x \leq 4

x^{2} = 4 x - 3

- 3 x^{2} + 2 x + 4 = 0

simplify (1/32)^{2/5}simplify

(\frac{1}{32})^{\frac{2}{5}}

Frequently Asked Questions (FAQ)

What is 2|x-4|-7<= 1 ?
The solution to 2|x-4|-7<= 1 is 0<= x<= 8