What are the solutions to the equation x^2-6x-9=-5x-3 ?

The solutions to the equation x^2-6x-9=-5x-3 are x=3,x=-2

Find the zeros of x^2-6x-9=-5x-3

The zeros of x^2-6x-9=-5x-3 are x=3,x=-2

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x^{2} - 6 x - 9 = - 5 x - 3

x = 3, x = - 2

Solution steps

x^{2} - 6 x - 9 = - 5 x - 3

Move

3

to the left side

x^{2} - 6 x - 6 = - 5 x

Move

5 x

to the left side

x^{2} - x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot ( - 6 )}{2 \cdot 1}

(- 1)^{2} - 4 \cdot 1 \cdot (- 6) = 5

x_{1, 2} = \frac{- ( - 1 ) \pm 5}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 5}{2 \cdot 1}, x_{2} = \frac{- ( - 1 ) - 5}{2 \cdot 1}

x = \frac{- ( - 1 ) + 5}{2 \cdot 1} : 3

x = \frac{- ( - 1 ) - 5}{2 \cdot 1} : - 2

The solutions to the quadratic equation are:

x = 3, x = - 2

4 x^{2} = 11 x + 45

m - 5 = - 10

4 (4 + 2 m) = 48

4 + y = 7

5 x - 15

What are the solutions to the equation x^2-6x-9=-5x-3 ?
The solutions to the equation x^2-6x-9=-5x-3 are x=3,x=-2
Find the zeros of x^2-6x-9=-5x-3
The zeros of x^2-6x-9=-5x-3 are x=3,x=-2