What are the solutions to the equation x^2-4x-12=0 ?

The solutions to the equation x^2-4x-12=0 are x=6,x=-2

Find the zeros of x^2-4x-12=0

The zeros of x^2-4x-12=0 are x=6,x=-2

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x^{2} - 4 x - 12 = 0

x = 6, x = - 2

Solution steps

x^{2} - 4 x - 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot ( - 12 )}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot (- 12) = 8

x_{1, 2} = \frac{- ( - 4 ) \pm 8}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 8}{2 \cdot 1}, x_{2} = \frac{- ( - 4 ) - 8}{2 \cdot 1}

x = \frac{- ( - 4 ) + 8}{2 \cdot 1} : 6

x = \frac{- ( - 4 ) - 8}{2 \cdot 1} : - 2

The solutions to the quadratic equation are:

x = 6, x = - 2

\frac{5}{25} = \frac{m}{125}

9 x^{2} - 66 x + 121

x^{2} + 7 x - 11 = 0

\frac{2 ( \frac{7}{24} )}{1 - ( \frac{7}{24} ) ^{2}}

(y^{\frac{2}{3}})^{- 9}

What are the solutions to the equation x^2-4x-12=0 ?
The solutions to the equation x^2-4x-12=0 are x=6,x=-2
Find the zeros of x^2-4x-12=0
The zeros of x^2-4x-12=0 are x=6,x=-2