What are the solutions to the equation x^2+7x-11=0 ?

The solutions to the equation x^2+7x-11=0 are x=(-7+sqrt(93))/2 ,x=(-7-sqrt(93))/2

Find the zeros of x^2+7x-11=0

The zeros of x^2+7x-11=0 are x=(-7+sqrt(93))/2 ,x=(-7-sqrt(93))/2

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x^{2} + 7 x - 11 = 0

x = \frac{- 7 + 93}{2}, x = \frac{- 7 - 93}{2}

Decimal Notation

x = 1.32182 \dots, x = - 8.32182 \dots

Solution steps

x^{2} + 7 x - 11 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 1 \cdot ( - 11 )}{2 \cdot 1}

7^{2} - 4 \cdot 1 \cdot (- 11) = 93

x_{1, 2} = \frac{- 7 \pm 93}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 7 + 93}{2 \cdot 1}, x_{2} = \frac{- 7 - 93}{2 \cdot 1}

x = \frac{- 7 + 93}{2 \cdot 1} : \frac{- 7 + 93}{2}

x = \frac{- 7 - 93}{2 \cdot 1} : \frac{- 7 - 93}{2}

The solutions to the quadratic equation are:

x = \frac{- 7 + 93}{2}, x = \frac{- 7 - 93}{2}

\frac{2 ( \frac{7}{24} )}{1 - ( \frac{7}{24} ) ^{2}}

(y^{\frac{2}{3}})^{- 9}

- 6 < 3 (x - 3) \leq 9

9 x (x + 6) - (3 x + 1)^{2} = 1

(\frac{4 a ^{3} b}{6 a ^{5} b ^{- 2}})^{3}

What are the solutions to the equation x^2+7x-11=0 ?
The solutions to the equation x^2+7x-11=0 are x=(-7+sqrt(93))/2 ,x=(-7-sqrt(93))/2
Find the zeros of x^2+7x-11=0
The zeros of x^2+7x-11=0 are x=(-7+sqrt(93))/2 ,x=(-7-sqrt(93))/2