What are the solutions to the equation x^2-4x=-4 ?

The solutions to the equation x^2-4x=-4 are x=2

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x^2-4x=-4

x^{2} - 4 x = - 4

x = 2

Solution steps

x^{2} - 4 x = - 4

Move

4

to the left side

x^{2} - 4 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot 4}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot 4 = 0

x_{1, 2} = \frac{- ( - 4 ) \pm 0}{2 \cdot 1}

x = \frac{- ( - 4 )}{2 \cdot 1}

\frac{- ( - 4 )}{2 \cdot 1} = 2

x = 2

The solution to the quadratic equation is:

x = 2

2 x + 9 = 0

- 4 (z + 3) = - 8

15 = - 5 x + 10

x^{2} - 14 x + 49 = 0

- \infty < x < \infty

What are the solutions to the equation x^2-4x=-4 ?
The solutions to the equation x^2-4x=-4 are x=2
Find the zeros of x^2-4x=-4
The zeros of x^2-4x=-4 are x=2