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3x-9x^2+10=0

解答

3 x - 9 x^{2} + 10 = 0

解答

x = - \frac{- 1 + 41}{6}, x = \frac{1 + 41}{6}

+1

十进制表示法

x = - 0.90052 \dots, x = 1.23385 \dots

求解步骤

3 x - 9 x^{2} + 10 = 0

改写成标准形式

a x^{2} + b x + c = 0

- 9 x^{2} + 3 x + 10 = 0

使用求根公式求解

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 ( - 9 ) \cdot 10}{2 ( - 9 )}

3^{2} - 4 (- 9) \cdot 10 = 341

x_{1, 2} = \frac{- 3 \pm 3 41}{2 ( - 9 )}

将解分隔开

x_{1} = \frac{- 3 + 3 41}{2 ( - 9 )}, x_{2} = \frac{- 3 - 3 41}{2 ( - 9 )}

x = \frac{- 3 + 3 41}{2 ( - 9 )} : - \frac{- 1 + 41}{6}

x = \frac{- 3 - 3 41}{2 ( - 9 )} : \frac{1 + 41}{6}

二次方程组的解是:

x = - \frac{- 1 + 41}{6}, x = \frac{1 + 41}{6}

流行的例子

x + 8 \leq 13

0.534=4.9t^2+0.442t

0.534 = 4.9 t^{2} + 0.442 t

因式分解 (x-3)^2-(x+4)^2 因式分解

(x - 3)^{2} - (x + 4)^{2}

(3p+1)/2-(2p)/5 =6

\frac{3 p + 1}{2} - \frac{2 p}{5} = 6

化简 9/(2-i)化简

\frac{9}{2 - i}