What are the solutions to the equation 8x^2-8x=6 ?

The solutions to the equation 8x^2-8x=6 are x= 3/2 ,x=-1/2

Find the zeros of 8x^2-8x=6

The zeros of 8x^2-8x=6 are x= 3/2 ,x=-1/2

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8 x^{2} - 8 x = 6

x = \frac{3}{2}, x = - \frac{1}{2}

Decimal Notation

x = 1.5, x = - 0.5

Solution steps

8 x^{2} - 8 x = 6

Move

6

to the left side

8 x^{2} - 8 x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 8 ( - 6 )}{2 \cdot 8}

(- 8)^{2} - 4 \cdot 8 (- 6) = 16

x_{1, 2} = \frac{- ( - 8 ) \pm 16}{2 \cdot 8}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 16}{2 \cdot 8}, x_{2} = \frac{- ( - 8 ) - 16}{2 \cdot 8}

x = \frac{- ( - 8 ) + 16}{2 \cdot 8} : \frac{3}{2}

x = \frac{- ( - 8 ) - 16}{2 \cdot 8} : - \frac{1}{2}

The solutions to the quadratic equation are:

x = \frac{3}{2}, x = - \frac{1}{2}

9 c^{2} - 4

6 a + 10 = a - 35

27 - 8 x^{3}

(x + 15)^{2} - 10 = 0

- 6 < 2 x + 2 \leq 0

What are the solutions to the equation 8x^2-8x=6 ?
The solutions to the equation 8x^2-8x=6 are x= 3/2 ,x=-1/2
Find the zeros of 8x^2-8x=6
The zeros of 8x^2-8x=6 are x= 3/2 ,x=-1/2