What are the solutions to the equation 3(x^2-9)=0 ?

The solutions to the equation 3(x^2-9)=0 are x=3,x=-3

Find the zeros of 3(x^2-9)=0

The zeros of 3(x^2-9)=0 are x=3,x=-3

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3 (x^{2} - 9) = 0

x = 3, x = - 3

Solution steps

3 (x^{2} - 9) = 0

Divide both sides by

3

x^{2} - 9 = 0

Move

9

to the right side

x^{2} = 9

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 9, x = - 9

9 = 3

- 9 = - 3

x = 3, x = - 3

(\frac{1}{3} x^{4} y^{- 3})^{- 2}

∣ x + 3 ∣ \leq 6

\frac{42}{4}

\frac{3 x - 5}{5} = - 4 x + 22

\frac{x + 3}{x + 16} > \frac{3}{x - 4}

What are the solutions to the equation 3(x^2-9)=0 ?
The solutions to the equation 3(x^2-9)=0 are x=3,x=-3
Find the zeros of 3(x^2-9)=0
The zeros of 3(x^2-9)=0 are x=3,x=-3