What are the solutions to the equation (x+7)^2=4 ?

The solutions to the equation (x+7)^2=4 are x=-5,x=-9

Find the zeros of (x+7)^2=4

The zeros of (x+7)^2=4 are x=-5,x=-9

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(x + 7)^{2} = 4

x = - 5, x = - 9

Solution steps

(x + 7)^{2} = 4

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 7 = 4 : x = - 5

Solve

x + 7 = - 4 : x = - 9

The solutions to the quadratic equation are:

x = - 5, x = - 9

- \frac{7 π}{4} - 2 π

6 (\frac{1}{3})

(\frac{x ^{6}}{27 y ^{- 9}})^{- \frac{2}{3}}

2 x^{2} - 9 x + 1 \geq - 3

48 r^{2} - 75

What are the solutions to the equation (x+7)^2=4 ?
The solutions to the equation (x+7)^2=4 are x=-5,x=-9
Find the zeros of (x+7)^2=4
The zeros of (x+7)^2=4 are x=-5,x=-9