What are the solutions to the equation 3x^2+1=0 ?

The solutions to the equation 3x^2+1=0 are x= 1/(sqrt(3))i,x=-1/(sqrt(3))i

Find the zeros of 3x^2+1=0

The zeros of 3x^2+1=0 are x= 1/(sqrt(3))i,x=-1/(sqrt(3))i

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3 x^{2} + 1 = 0

x = \frac{1}{3} i, x = - \frac{1}{3} i

Solution steps

3 x^{2} + 1 = 0

Move

1

to the right side

3 x^{2} = - 1

Divide both sides by

3

x^{2} = - \frac{1}{3}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - \frac{1}{3}, x = - - \frac{1}{3}

- \frac{1}{3} = \frac{1}{3} i

- - \frac{1}{3} = - \frac{1}{3} i

x = \frac{1}{3} i, x = - \frac{1}{3} i

x^{5} - x^{4} + x - 1

∣ a + 9 ∣ + 2 \geq 6

9 (9 b + 1) + 9 b

3 \cdot 9 + 10 \cdot \frac{36}{6}

What are the solutions to the equation 3x^2+1=0 ?
The solutions to the equation 3x^2+1=0 are x= 1/(sqrt(3))i,x=-1/(sqrt(3))i
Find the zeros of 3x^2+1=0
The zeros of 3x^2+1=0 are x= 1/(sqrt(3))i,x=-1/(sqrt(3))i