What are the solutions to the equation 4n^2=-8 ?

The solutions to the equation 4n^2=-8 are n=sqrt(2)i,n=-sqrt(2)i

Find the zeros of 4n^2=-8

The zeros of 4n^2=-8 are n=sqrt(2)i,n=-sqrt(2)i

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4 n^{2} = - 8

n = 2 i, n = - 2 i

Solution steps

4 n^{2} = - 8

Divide both sides by

4

n^{2} = - 2

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

n = - 2, n = - - 2

- 2 = 2 i

- - 2 = - 2 i

n = 2 i, n = - 2 i

32 a^{4} - 4 a

x^{2} + 6 x - 135

x - 4 < 2 or 4 x - 1 > 4

3 x^{3} - 2 x^{2} - 12 x + 8

32 + m = - 36

What are the solutions to the equation 4n^2=-8 ?
The solutions to the equation 4n^2=-8 are n=sqrt(2)i,n=-sqrt(2)i
Find the zeros of 4n^2=-8
The zeros of 4n^2=-8 are n=sqrt(2)i,n=-sqrt(2)i