What are the solutions to the equation x^2+10x+61=0 ?

The solutions to the equation x^2+10x+61=0 are x=-5+6i,x=-5-6i

Find the zeros of x^2+10x+61=0

The zeros of x^2+10x+61=0 are x=-5+6i,x=-5-6i

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x^{2} + 10 x + 61 = 0

x = - 5 + 6 i, x = - 5 - 6 i

Solution steps

x^{2} + 10 x + 61 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 1 \cdot 61}{2 \cdot 1}

Simplify

1 0^{2} - 4 \cdot 1 \cdot 61 : 12 i

x_{1, 2} = \frac{- 10 \pm 12 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 10 + 12 i}{2 \cdot 1}, x_{2} = \frac{- 10 - 12 i}{2 \cdot 1}

x = \frac{- 10 + 12 i}{2 \cdot 1} : - 5 + 6 i

x = \frac{- 10 - 12 i}{2 \cdot 1} : - 5 - 6 i

The solutions to the quadratic equation are:

x = - 5 + 6 i, x = - 5 - 6 i

- 8 \leq 3 x - 5 \leq 7

5 x - 5 = 3 x + 3

5 + 4 (n + 9) = - 3

69 - 31 n - 42 n = 69

4 x^{2} - 8 x - 320

What are the solutions to the equation x^2+10x+61=0 ?
The solutions to the equation x^2+10x+61=0 are x=-5+6i,x=-5-6i
Find the zeros of x^2+10x+61=0
The zeros of x^2+10x+61=0 are x=-5+6i,x=-5-6i