What are the solutions to the equation 6x^2+2x-1=0 ?

The solutions to the equation 6x^2+2x-1=0 are x=(-1+sqrt(7))/6 ,x=-(1+sqrt(7))/6

Find the zeros of 6x^2+2x-1=0

The zeros of 6x^2+2x-1=0 are x=(-1+sqrt(7))/6 ,x=-(1+sqrt(7))/6

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6 x^{2} + 2 x - 1 = 0

x = \frac{- 1 + 7}{6}, x = - \frac{1 + 7}{6}

Decimal Notation

x = 0.27429 \dots, x = - 0.60762 \dots

Solution steps

6 x^{2} + 2 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 6 ( - 1 )}{2 \cdot 6}

2^{2} - 4 \cdot 6 (- 1) = 27

x_{1, 2} = \frac{- 2 \pm 2 7}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- 2 + 2 7}{2 \cdot 6}, x_{2} = \frac{- 2 - 2 7}{2 \cdot 6}

x = \frac{- 2 + 2 7}{2 \cdot 6} : \frac{- 1 + 7}{6}

x = \frac{- 2 - 2 7}{2 \cdot 6} : - \frac{1 + 7}{6}

The solutions to the quadratic equation are:

x = \frac{- 1 + 7}{6}, x = - \frac{1 + 7}{6}

x > 5 and x < 7

2 x^{2} - 16 x + 30 = 0

\frac{y}{5} + \frac{3}{10} = \frac{y + 2}{7}

- 7 y^{2} - 12 y + 4

What are the solutions to the equation 6x^2+2x-1=0 ?
The solutions to the equation 6x^2+2x-1=0 are x=(-1+sqrt(7))/6 ,x=-(1+sqrt(7))/6
Find the zeros of 6x^2+2x-1=0
The zeros of 6x^2+2x-1=0 are x=(-1+sqrt(7))/6 ,x=-(1+sqrt(7))/6