What are the solutions to the equation 8r^2+8r+2=0 ?

The solutions to the equation 8r^2+8r+2=0 are r=-1/2

Find the zeros of 8r^2+8r+2=0

The zeros of 8r^2+8r+2=0 are r=-1/2

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8 r^{2} + 8 r + 2 = 0

r = - \frac{1}{2}

Decimal Notation

r = - 0.5

Solution steps

8 r^{2} + 8 r + 2 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 8 \cdot 2}{2 \cdot 8}

8^{2} - 4 \cdot 8 \cdot 2 = 0

r_{1, 2} = \frac{- 8 \pm 0}{2 \cdot 8}

r = \frac{- 8}{2 \cdot 8}

\frac{- 8}{2 \cdot 8} = - \frac{1}{2}

r = - \frac{1}{2}

The solution to the quadratic equation is:

r = - \frac{1}{2}

∣ 2 t + 9 ∣ = 2

- 9 x + 2.3 = - 3 x + 1.7

x^{2} - 15 x + 56

- 2 < x \leq 4

15 = \frac{1}{3} (x + 9)

What are the solutions to the equation 8r^2+8r+2=0 ?
The solutions to the equation 8r^2+8r+2=0 are r=-1/2
Find the zeros of 8r^2+8r+2=0
The zeros of 8r^2+8r+2=0 are r=-1/2