What are the solutions to the equation x^2+4x-26=0 ?

The solutions to the equation x^2+4x-26=0 are x=-2+sqrt(30),x=-2-sqrt(30)

Find the zeros of x^2+4x-26=0

The zeros of x^2+4x-26=0 are x=-2+sqrt(30),x=-2-sqrt(30)

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x^{2} + 4 x - 26 = 0

x = - 2 + 30, x = - 2 - 30

Decimal Notation

x = 3.47722 \dots, x = - 7.47722 \dots

Solution steps

x^{2} + 4 x - 26 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot ( - 26 )}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot (- 26) = 230

x_{1, 2} = \frac{- 4 \pm 2 30}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 4 + 2 30}{2 \cdot 1}, x_{2} = \frac{- 4 - 2 30}{2 \cdot 1}

x = \frac{- 4 + 2 30}{2 \cdot 1} : - 2 + 30

x = \frac{- 4 - 2 30}{2 \cdot 1} : - 2 - 30

The solutions to the quadratic equation are:

x = - 2 + 30, x = - 2 - 30

2 (y + 1) + 7 = 3 (y - 2) + 2 y

4 x^{2} - 17 x + 15 = 0

x^{2} + 2 x - 264 = 0

(- 4) + (- 8) - (- 3) + (+ 6) - (+ 10)

x^{2} - 14 x + 17 = 0

What are the solutions to the equation x^2+4x-26=0 ?
The solutions to the equation x^2+4x-26=0 are x=-2+sqrt(30),x=-2-sqrt(30)
Find the zeros of x^2+4x-26=0
The zeros of x^2+4x-26=0 are x=-2+sqrt(30),x=-2-sqrt(30)