What are the solutions to the equation 3.7^2=x^2+1.1^2 ?

The solutions to the equation 3.7^2=x^2+1.1^2 are x=(2sqrt(78))/5 ,x=-(2sqrt(78))/5

Find the zeros of 3.7^2=x^2+1.1^2

The zeros of 3.7^2=x^2+1.1^2 are x=(2sqrt(78))/5 ,x=-(2sqrt(78))/5

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3. 7^{2} = x^{2} + 1. 1^{2}

x = \frac{2 78}{5}, x = - \frac{2 78}{5}

Decimal Notation

x = 3.53270 \dots, x = - 3.53270 \dots

Solution steps

3. 7^{2} = x^{2} + 1. 1^{2}

Switch sides

x^{2} + 1. 1^{2} = 3. 7^{2}

Move

1. 1^{2}

to the right side

x^{2} = 12.48

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 12.48, x = - 12.48

12.48 = \frac{2 78}{5}

- 12.48 = - \frac{2 78}{5}

x = \frac{2 78}{5}, x = - \frac{2 78}{5}

315 \cdot \frac{π}{180}

\frac{2 i}{( 1 + i )}

- 25 - - 16

\frac{x}{25} = \frac{7}{10}

x^{3} + 5 x^{2} - 4 x - 20 \geq 0

What are the solutions to the equation 3.7^2=x^2+1.1^2 ?
The solutions to the equation 3.7^2=x^2+1.1^2 are x=(2sqrt(78))/5 ,x=-(2sqrt(78))/5
Find the zeros of 3.7^2=x^2+1.1^2
The zeros of 3.7^2=x^2+1.1^2 are x=(2sqrt(78))/5 ,x=-(2sqrt(78))/5