What is 1/3 >= (2x-9)/(12)> 1/6 ?

The solution to 1/3 >= (2x-9)/(12)> 1/6 is 11/2 <x<= 13/2

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1/3 >= (2x-9)/(12)> 1/6

\frac{1}{3} \geq \frac{2 x - 9}{12} > \frac{1}{6}

\frac{11}{2} < x \leq \frac{13}{2}

Interval Notation

(\frac{11}{2}, \frac{13}{2}]

Decimal Notation

5.5 < x \leq 6.5

Solution steps

\frac{1}{3} \geq \frac{2 x - 9}{12} > \frac{1}{6}

a \geq u > b

then

a \geq u and u > b

\frac{1}{3} \geq \frac{2 x - 9}{12} and \frac{2 x - 9}{12} > \frac{1}{6}

\frac{1}{3} \geq \frac{2 x - 9}{12} : x \leq \frac{13}{2}

\frac{2 x - 9}{12} > \frac{1}{6} : x > \frac{11}{2}

Combine the intervals

x \leq \frac{13}{2} and x > \frac{11}{2}

Merge Overlapping Intervals

\frac{11}{2} < x \leq \frac{13}{2}

- - 144

\frac{1}{2} y = 24

\frac{3}{7} + \frac{2}{5}

\frac{4 m}{m - 6} - \frac{24}{m - 6}

a + a + a = 30

What is 1/3 >= (2x-9)/(12)> 1/6 ?
The solution to 1/3 >= (2x-9)/(12)> 1/6 is 11/2 <x<= 13/2