What is (16x^{-2}y^{-3})/(12x^4y^{-5)} ?

The solution to (16x^{-2}y^{-3})/(12x^4y^{-5)} is (4y^2)/(3x^6)

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simplify (16x^{-2}y^{-3})/(12x^4y^{-5)}

simplify

\frac{16 x ^{- 2} y ^{- 3}}{12 x ^{4} y ^{- 5}}

\frac{4 y ^{2}}{3 x ^{6}}

Solution steps

\frac{16 x ^{- 2} y ^{- 3}}{12 x ^{4} y ^{- 5}}

Factor the number:

16 = 4 \cdot 4

= \frac{4 \cdot 4 x ^{- 2} y ^{- 3}}{12 x ^{4} y ^{- 5}}

Factor the number:

12 = 4 \cdot 3

= \frac{4 \cdot 4 x ^{- 2} y ^{- 3}}{4 \cdot 3 x ^{4} y ^{- 5}}

Cancel the common factor:

4

= \frac{4 x ^{- 2} y ^{- 3}}{3 x ^{4} y ^{- 5}}

Simplify

\frac{y ^{- 3}}{y ^{- 5}} : y^{2}

= \frac{4 x ^{- 2} y ^{2}}{3 x ^{4}}

Simplify

\frac{x ^{- 2}}{x ^{4}} : \frac{1}{x ^{6}}

= \frac{4 y ^{2}}{3 x ^{6}}

\frac{3 i}{5 + 3 i}

- x + 4 = 3 x

8 \cdot (\frac{3}{2})

2 a^{2} + 13 a + 15

x^{2} + (x + 7)^{2} = 1 7^{2}

What is (16x^{-2}y^{-3})/(12x^4y^{-5)} ?
The solution to (16x^{-2}y^{-3})/(12x^4y^{-5)} is (4y^2)/(3x^6)