What are the solutions to the equation 6x^2+18x=x-12 ?

The solutions to the equation 6x^2+18x=x-12 are x=-4/3 ,x=-3/2

Find the zeros of 6x^2+18x=x-12

The zeros of 6x^2+18x=x-12 are x=-4/3 ,x=-3/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

6 x^{2} + 18 x = x - 12

x = - \frac{4}{3}, x = - \frac{3}{2}

Decimal Notation

x = - 1.33333 \dots, x = - 1.5

Solution steps

6 x^{2} + 18 x = x - 12

Move

12

to the left side

6 x^{2} + 18 x + 12 = x

Move

x

to the left side

6 x^{2} + 17 x + 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 17 \pm 1 7 ^{2} - 4 \cdot 6 \cdot 12}{2 \cdot 6}

1 7^{2} - 4 \cdot 6 \cdot 12 = 1

x_{1, 2} = \frac{- 17 \pm 1}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- 17 + 1}{2 \cdot 6}, x_{2} = \frac{- 17 - 1}{2 \cdot 6}

x = \frac{- 17 + 1}{2 \cdot 6} : - \frac{4}{3}

x = \frac{- 17 - 1}{2 \cdot 6} : - \frac{3}{2}

The solutions to the quadratic equation are:

x = - \frac{4}{3}, x = - \frac{3}{2}

1 + 3 x = 7 x - 9

\frac{50}{18}

2 x \leq 2 (x - 1)

x + \frac{x}{2} = 3

x^{2} - 9 x + 20 < 0

What are the solutions to the equation 6x^2+18x=x-12 ?
The solutions to the equation 6x^2+18x=x-12 are x=-4/3 ,x=-3/2
Find the zeros of 6x^2+18x=x-12
The zeros of 6x^2+18x=x-12 are x=-4/3 ,x=-3/2