What is (4x^2)/(5y)*(7y)/(12x^4) ?

The solution to (4x^2)/(5y)*(7y)/(12x^4) is 7/(15x^2)

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simplify (4x^2)/(5y)*(7y)/(12x^4)

simplify

\frac{4 x ^{2}}{5 y} \cdot \frac{7 y}{12 x ^{4}}

\frac{7}{15 x ^{2}}

Solution steps

\frac{4 x ^{2}}{5 y} \cdot \frac{7 y}{12 x ^{4}}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{4 x ^{2} \cdot 7 y}{5 y \cdot 12 x ^{4}}

Cancel the common factor:

y

= \frac{4 x ^{2} \cdot 7}{5 \cdot 12 x ^{4}}

Factor the number:

12 = 4 \cdot 3

= \frac{4 x ^{2} \cdot 7}{5 \cdot 4 \cdot 3 x ^{4}}

Cancel the common factor:

4

= \frac{x ^{2} \cdot 7}{5 \cdot 3 x ^{4}}

Simplify

\frac{x ^{2}}{x ^{4}} : \frac{1}{x ^{2}}

= \frac{7}{5 \cdot 3 x ^{2}}

Multiply the numbers:

5 \cdot 3 = 15

= \frac{7}{15 x ^{2}}

x = 0.2 \times 2 + (2 - 0.2) \times 1

(n - 9) (4 n + 1) = 0

3 x^{2} - 10 x - 9 = 0

3 x y^{2} - 27 x^{3}

64 x^{2} y^{2} - 144 z^{2}

What is (4x^2)/(5y)*(7y)/(12x^4) ?
The solution to (4x^2)/(5y)*(7y)/(12x^4) is 7/(15x^2)