What are the solutions to the equation 2x^2+1=0 ?

The solutions to the equation 2x^2+1=0 are x= 1/(sqrt(2))i,x=-1/(sqrt(2))i

Find the zeros of 2x^2+1=0

The zeros of 2x^2+1=0 are x= 1/(sqrt(2))i,x=-1/(sqrt(2))i

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2 x^{2} + 1 = 0

x = \frac{1}{2} i, x = - \frac{1}{2} i

Solution steps

2 x^{2} + 1 = 0

Move

1

to the right side

2 x^{2} = - 1

Divide both sides by

2

x^{2} = - \frac{1}{2}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - \frac{1}{2}, x = - - \frac{1}{2}

- \frac{1}{2} = \frac{1}{2} i

- - \frac{1}{2} = - \frac{1}{2} i

x = \frac{1}{2} i, x = - \frac{1}{2} i

25 x^{2} + 9 = 30 x

\frac{7}{6} x = 140

1188870 = - 2.06 x^{2} + 77.83 x + 745

\frac{6 - i 2}{i 3}

\frac{4}{3} \times π 3.3 5^{3}

What are the solutions to the equation 2x^2+1=0 ?
The solutions to the equation 2x^2+1=0 are x= 1/(sqrt(2))i,x=-1/(sqrt(2))i
Find the zeros of 2x^2+1=0
The zeros of 2x^2+1=0 are x= 1/(sqrt(2))i,x=-1/(sqrt(2))i