What are the solutions to the equation m^2-2m+2=0 ?

The solutions to the equation m^2-2m+2=0 are m=1+i,m=1-i

Find the zeros of m^2-2m+2=0

The zeros of m^2-2m+2=0 are m=1+i,m=1-i

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m^{2} - 2 m + 2 = 0

m = 1 + i, m = 1 - i

Solution steps

m^{2} - 2 m + 2 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot 2}{2 \cdot 1}

Simplify

(- 2)^{2} - 4 \cdot 1 \cdot 2 : 2 i

m_{1, 2} = \frac{- ( - 2 ) \pm 2 i}{2 \cdot 1}

Separate the solutions

m_{1} = \frac{- ( - 2 ) + 2 i}{2 \cdot 1}, m_{2} = \frac{- ( - 2 ) - 2 i}{2 \cdot 1}

m = \frac{- ( - 2 ) + 2 i}{2 \cdot 1} : 1 + i

m = \frac{- ( - 2 ) - 2 i}{2 \cdot 1} : 1 - i

The solutions to the quadratic equation are:

m = 1 + i, m = 1 - i

15 x^{2} + 74 x - 32

4 x - 9 > - 1 or - x + 5 \geq 4

∣ 4 x + 3 ∣ = 7

3 a + 9

4 x < 8

What are the solutions to the equation m^2-2m+2=0 ?
The solutions to the equation m^2-2m+2=0 are m=1+i,m=1-i
Find the zeros of m^2-2m+2=0
The zeros of m^2-2m+2=0 are m=1+i,m=1-i