What are the solutions to the equation x^2-4x-2=-x^2+4 ?

The solutions to the equation x^2-4x-2=-x^2+4 are x=3,x=-1

Find the zeros of x^2-4x-2=-x^2+4

The zeros of x^2-4x-2=-x^2+4 are x=3,x=-1

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x^{2} - 4 x - 2 = - x^{2} + 4

x = 3, x = - 1

Solution steps

x^{2} - 4 x - 2 = - x^{2} + 4

Move

4

to the left side

x^{2} - 4 x - 6 = - x^{2}

Move

x^{2}

to the left side

2 x^{2} - 4 x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 2 ( - 6 )}{2 \cdot 2}

(- 4)^{2} - 4 \cdot 2 (- 6) = 8

x_{1, 2} = \frac{- ( - 4 ) \pm 8}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 8}{2 \cdot 2}, x_{2} = \frac{- ( - 4 ) - 8}{2 \cdot 2}

x = \frac{- ( - 4 ) + 8}{2 \cdot 2} : 3

x = \frac{- ( - 4 ) - 8}{2 \cdot 2} : - 1

The solutions to the quadratic equation are:

x = 3, x = - 1

15 x^{2} - 14 x + 3 = 0

1000 lo g_{2} (1000)

18 = \frac{k}{5}

2 x^{3} - 16 x^{2} - 40 x

x^{2} y^{2} - 81

What are the solutions to the equation x^2-4x-2=-x^2+4 ?
The solutions to the equation x^2-4x-2=-x^2+4 are x=3,x=-1
Find the zeros of x^2-4x-2=-x^2+4
The zeros of x^2-4x-2=-x^2+4 are x=3,x=-1