What are the solutions to the equation 4x^2-20x+32=0 ?

The solutions to the equation 4x^2-20x+32=0 are x= 5/2+i(sqrt(7))/2 ,x= 5/2-i(sqrt(7))/2

Find the zeros of 4x^2-20x+32=0

The zeros of 4x^2-20x+32=0 are x= 5/2+i(sqrt(7))/2 ,x= 5/2-i(sqrt(7))/2

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4 x^{2} - 20 x + 32 = 0

x = \frac{5}{2} + i \frac{7}{2}, x = \frac{5}{2} - i \frac{7}{2}

Solution steps

4 x^{2} - 20 x + 32 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 20 ) \pm ( - 20 ) ^{2} - 4 \cdot 4 \cdot 32}{2 \cdot 4}

Simplify

(- 20)^{2} - 4 \cdot 4 \cdot 32 : 47 i

x_{1, 2} = \frac{- ( - 20 ) \pm 4 7 i}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 20 ) + 4 7 i}{2 \cdot 4}, x_{2} = \frac{- ( - 20 ) - 4 7 i}{2 \cdot 4}

x = \frac{- ( - 20 ) + 4 7 i}{2 \cdot 4} : \frac{5}{2} + i \frac{7}{2}

x = \frac{- ( - 20 ) - 4 7 i}{2 \cdot 4} : \frac{5}{2} - i \frac{7}{2}

The solutions to the quadratic equation are:

x = \frac{5}{2} + i \frac{7}{2}, x = \frac{5}{2} - i \frac{7}{2}

- - 96

- 1 = x^{2} + 2 x - 1

6 + 3 ∣ 4 + 4 x ∣ = 18

4 x - 7 < 9

- 0.7 + \frac{b}{3} = - 1.9

What are the solutions to the equation 4x^2-20x+32=0 ?
The solutions to the equation 4x^2-20x+32=0 are x= 5/2+i(sqrt(7))/2 ,x= 5/2-i(sqrt(7))/2
Find the zeros of 4x^2-20x+32=0
The zeros of 4x^2-20x+32=0 are x= 5/2+i(sqrt(7))/2 ,x= 5/2-i(sqrt(7))/2