What are the solutions to the equation 4(x-2)^2+9=25 ?

The solutions to the equation 4(x-2)^2+9=25 are x=4,x=0

Find the zeros of 4(x-2)^2+9=25

The zeros of 4(x-2)^2+9=25 are x=4,x=0

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4 (x - 2)^{2} + 9 = 25

x = 4, x = 0

Solution steps

4 (x - 2)^{2} + 9 = 25

Move

9

to the right side

4 (x - 2)^{2} = 16

Divide both sides by

4

(x - 2)^{2} = 4

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 2 = 4 : x = 4

Solve

x - 2 = - 4 : x = 0

The solutions to the quadratic equation are:

x = 4, x = 0

5 x^{2} = 40 x + 5

p^{2} + 10 p + 16

y - x^{3} y^{2}

- \frac{i}{i}

\frac{7}{6} + \frac{1}{3}

What are the solutions to the equation 4(x-2)^2+9=25 ?
The solutions to the equation 4(x-2)^2+9=25 are x=4,x=0
Find the zeros of 4(x-2)^2+9=25
The zeros of 4(x-2)^2+9=25 are x=4,x=0