What are the solutions to the equation q^2-4q-3=0 ?

The solutions to the equation q^2-4q-3=0 are q=2+sqrt(7),q=2-sqrt(7)

Find the zeros of q^2-4q-3=0

The zeros of q^2-4q-3=0 are q=2+sqrt(7),q=2-sqrt(7)

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q^{2} - 4 q - 3 = 0

q = 2 + 7, q = 2 - 7

Decimal Notation

q = 4.64575 \dots, q = - 0.64575 \dots

Solution steps

q^{2} - 4 q - 3 = 0

Solve with the quadratic formula

q_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot ( - 3 )}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot (- 3) = 27

q_{1, 2} = \frac{- ( - 4 ) \pm 2 7}{2 \cdot 1}

Separate the solutions

q_{1} = \frac{- ( - 4 ) + 2 7}{2 \cdot 1}, q_{2} = \frac{- ( - 4 ) - 2 7}{2 \cdot 1}

q = \frac{- ( - 4 ) + 2 7}{2 \cdot 1} : 2 + 7

q = \frac{- ( - 4 ) - 2 7}{2 \cdot 1} : 2 - 7

The solutions to the quadratic equation are:

q = 2 + 7, q = 2 - 7

- \frac{5}{4} + 8

b^{2} = 169 + 225 - 390 (0.12)

12 - x = x^{2}

\frac{x + 1}{x - 1} < 0

\frac{2 b - 2}{5} = 4

What are the solutions to the equation q^2-4q-3=0 ?
The solutions to the equation q^2-4q-3=0 are q=2+sqrt(7),q=2-sqrt(7)
Find the zeros of q^2-4q-3=0
The zeros of q^2-4q-3=0 are q=2+sqrt(7),q=2-sqrt(7)