What are the solutions to the equation 2x^2+17x+21=0 ?

The solutions to the equation 2x^2+17x+21=0 are x=-3/2 ,x=-7

Find the zeros of 2x^2+17x+21=0

The zeros of 2x^2+17x+21=0 are x=-3/2 ,x=-7

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2 x^{2} + 17 x + 21 = 0

x = - \frac{3}{2}, x = - 7

Decimal Notation

x = - 1.5, x = - 7

Solution steps

2 x^{2} + 17 x + 21 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 17 \pm 1 7 ^{2} - 4 \cdot 2 \cdot 21}{2 \cdot 2}

1 7^{2} - 4 \cdot 2 \cdot 21 = 11

x_{1, 2} = \frac{- 17 \pm 11}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 17 + 11}{2 \cdot 2}, x_{2} = \frac{- 17 - 11}{2 \cdot 2}

x = \frac{- 17 + 11}{2 \cdot 2} : - \frac{3}{2}

x = \frac{- 17 - 11}{2 \cdot 2} : - 7

The solutions to the quadratic equation are:

x = - \frac{3}{2}, x = - 7

\frac{23}{12} = \frac{1}{2} v + \frac{15}{4} - 6 v

\frac{y}{9} = 3

\frac{6 ^{- 5}}{6 ^{- 2}}

24 a - 12 ab

(- \frac{3}{2})^{2}

What are the solutions to the equation 2x^2+17x+21=0 ?
The solutions to the equation 2x^2+17x+21=0 are x=-3/2 ,x=-7
Find the zeros of 2x^2+17x+21=0
The zeros of 2x^2+17x+21=0 are x=-3/2 ,x=-7