What are the solutions to the equation 8b^2-13b+6=5b^2 ?

The solutions to the equation 8b^2-13b+6=5b^2 are b=(13+sqrt(97))/6 ,b=(13-sqrt(97))/6

Find the zeros of 8b^2-13b+6=5b^2

The zeros of 8b^2-13b+6=5b^2 are b=(13+sqrt(97))/6 ,b=(13-sqrt(97))/6

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8 b^{2} - 13 b + 6 = 5 b^{2}

b = \frac{13 + 97}{6}, b = \frac{13 - 97}{6}

Decimal Notation

b = 3.80814 \dots, b = 0.52519 \dots

Solution steps

8 b^{2} - 13 b + 6 = 5 b^{2}

Move

5 b^{2}

to the left side

3 b^{2} - 13 b + 6 = 0

Solve with the quadratic formula

b_{1, 2} = \frac{- ( - 13 ) \pm ( - 13 ) ^{2} - 4 \cdot 3 \cdot 6}{2 \cdot 3}

(- 13)^{2} - 4 \cdot 3 \cdot 6 = 97

b_{1, 2} = \frac{- ( - 13 ) \pm 97}{2 \cdot 3}

Separate the solutions

b_{1} = \frac{- ( - 13 ) + 97}{2 \cdot 3}, b_{2} = \frac{- ( - 13 ) - 97}{2 \cdot 3}

b = \frac{- ( - 13 ) + 97}{2 \cdot 3} : \frac{13 + 97}{6}

b = \frac{- ( - 13 ) - 97}{2 \cdot 3} : \frac{13 - 97}{6}

The solutions to the quadratic equation are:

b = \frac{13 + 97}{6}, b = \frac{13 - 97}{6}

\frac{( 3 k ^{3} ) ^{3}}{12 k ^{- 8}}

\frac{9 + 7 i}{7 - 4 i}

- 3 < 2 x + 1 < 5

6 y^{2} - y - 12

\frac{5}{9} \times \frac{8}{11}

What are the solutions to the equation 8b^2-13b+6=5b^2 ?
The solutions to the equation 8b^2-13b+6=5b^2 are b=(13+sqrt(97))/6 ,b=(13-sqrt(97))/6
Find the zeros of 8b^2-13b+6=5b^2
The zeros of 8b^2-13b+6=5b^2 are b=(13+sqrt(97))/6 ,b=(13-sqrt(97))/6