What are the solutions to the equation -3x^2-11x+2=0 ?

The solutions to the equation -3x^2-11x+2=0 are x=-(11+sqrt(145))/6 ,x=(sqrt(145)-11)/6

Find the zeros of -3x^2-11x+2=0

The zeros of -3x^2-11x+2=0 are x=-(11+sqrt(145))/6 ,x=(sqrt(145)-11)/6

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- 3 x^{2} - 11 x + 2 = 0

x = - \frac{11 + 145}{6}, x = \frac{145 - 11}{6}

Decimal Notation

x = - 3.84026 \dots, x = 0.17359 \dots

Solution steps

- 3 x^{2} - 11 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 11 ) \pm ( - 11 ) ^{2} - 4 ( - 3 ) \cdot 2}{2 ( - 3 )}

(- 11)^{2} - 4 (- 3) \cdot 2 = 145

x_{1, 2} = \frac{- ( - 11 ) \pm 145}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- ( - 11 ) + 145}{2 ( - 3 )}, x_{2} = \frac{- ( - 11 ) - 145}{2 ( - 3 )}

x = \frac{- ( - 11 ) + 145}{2 ( - 3 )} : - \frac{11 + 145}{6}

x = \frac{- ( - 11 ) - 145}{2 ( - 3 )} : \frac{145 - 11}{6}

The solutions to the quadratic equation are:

x = - \frac{11 + 145}{6}, x = \frac{145 - 11}{6}

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What are the solutions to the equation -3x^2-11x+2=0 ?
The solutions to the equation -3x^2-11x+2=0 are x=-(11+sqrt(145))/6 ,x=(sqrt(145)-11)/6
Find the zeros of -3x^2-11x+2=0
The zeros of -3x^2-11x+2=0 are x=-(11+sqrt(145))/6 ,x=(sqrt(145)-11)/6