What are the solutions to the equation 6x^2-3x=1 ?

The solutions to the equation 6x^2-3x=1 are x=(3+sqrt(33))/(12),x=(3-sqrt(33))/(12)

Find the zeros of 6x^2-3x=1

The zeros of 6x^2-3x=1 are x=(3+sqrt(33))/(12),x=(3-sqrt(33))/(12)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

6 x^{2} - 3 x = 1

x = \frac{3 + 33}{12}, x = \frac{3 - 33}{12}

Decimal Notation

x = 0.72871 \dots, x = - 0.22871 \dots

Solution steps

6 x^{2} - 3 x = 1

Move

1

to the left side

6 x^{2} - 3 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 6 ( - 1 )}{2 \cdot 6}

(- 3)^{2} - 4 \cdot 6 (- 1) = 33

x_{1, 2} = \frac{- ( - 3 ) \pm 33}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 33}{2 \cdot 6}, x_{2} = \frac{- ( - 3 ) - 33}{2 \cdot 6}

x = \frac{- ( - 3 ) + 33}{2 \cdot 6} : \frac{3 + 33}{12}

x = \frac{- ( - 3 ) - 33}{2 \cdot 6} : \frac{3 - 33}{12}

The solutions to the quadratic equation are:

x = \frac{3 + 33}{12}, x = \frac{3 - 33}{12}

- 5 (5 x + 3) - 5 x + 1 = - 44

4 (e - 1) = 6 (2 e - 7) - 4 (2 e - 12)

3 x + 5 < 6 x - 1

x = 1.8 x^{2} - 1.296 x + 0.23328

\frac{3}{8} \cdot \frac{5}{7}

What are the solutions to the equation 6x^2-3x=1 ?
The solutions to the equation 6x^2-3x=1 are x=(3+sqrt(33))/(12),x=(3-sqrt(33))/(12)
Find the zeros of 6x^2-3x=1
The zeros of 6x^2-3x=1 are x=(3+sqrt(33))/(12),x=(3-sqrt(33))/(12)