What are the solutions to the equation 4u^2+4u+1=0 ?

The solutions to the equation 4u^2+4u+1=0 are u=-1/2

Find the zeros of 4u^2+4u+1=0

The zeros of 4u^2+4u+1=0 are u=-1/2

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4 u^{2} + 4 u + 1 = 0

u = - \frac{1}{2}

Decimal Notation

u = - 0.5

Solution steps

4 u^{2} + 4 u + 1 = 0

Solve with the quadratic formula

u_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 4 \cdot 1}{2 \cdot 4}

4^{2} - 4 \cdot 4 \cdot 1 = 0

u_{1, 2} = \frac{- 4 \pm 0}{2 \cdot 4}

u = \frac{- 4}{2 \cdot 4}

\frac{- 4}{2 \cdot 4} = - \frac{1}{2}

u = - \frac{1}{2}

The solution to the quadratic equation is:

u = - \frac{1}{2}

x^{2} + 15 x y - 76 y^{2}

(2 - 3 i) (1 + 7 i)

(2 + i 3) (2 - i 3)

4 v^{2} - 15 v + 16 = 6

- 3 x + 6 < 15 or 4 x - 1 \geq 3

What are the solutions to the equation 4u^2+4u+1=0 ?
The solutions to the equation 4u^2+4u+1=0 are u=-1/2
Find the zeros of 4u^2+4u+1=0
The zeros of 4u^2+4u+1=0 are u=-1/2