What are the solutions to the equation -3x^2+4x-6=0 ?

The solutions to the equation -3x^2+4x-6=0 are x= 2/3-i(sqrt(14))/3 ,x= 2/3+i(sqrt(14))/3

Find the zeros of -3x^2+4x-6=0

The zeros of -3x^2+4x-6=0 are x= 2/3-i(sqrt(14))/3 ,x= 2/3+i(sqrt(14))/3

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- 3 x^{2} + 4 x - 6 = 0

x = \frac{2}{3} - i \frac{14}{3}, x = \frac{2}{3} + i \frac{14}{3}

Solution steps

- 3 x^{2} + 4 x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 ( - 3 ) ( - 6 )}{2 ( - 3 )}

Simplify

4^{2} - 4 (- 3) (- 6) : 214 i

x_{1, 2} = \frac{- 4 \pm 2 14 i}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- 4 + 2 14 i}{2 ( - 3 )}, x_{2} = \frac{- 4 - 2 14 i}{2 ( - 3 )}

x = \frac{- 4 + 2 14 i}{2 ( - 3 )} : \frac{2}{3} - i \frac{14}{3}

x = \frac{- 4 - 2 14 i}{2 ( - 3 )} : \frac{2}{3} + i \frac{14}{3}

The solutions to the quadratic equation are:

x = \frac{2}{3} - i \frac{14}{3}, x = \frac{2}{3} + i \frac{14}{3}

- 3 = - 2 (- 3)^{3} - 3

3 (3)

9 - (- 5)

x^{3} - x^{2} - 5 x + 5

x^{2} - 12 x + 19 = - 2 x - 5

What are the solutions to the equation -3x^2+4x-6=0 ?
The solutions to the equation -3x^2+4x-6=0 are x= 2/3-i(sqrt(14))/3 ,x= 2/3+i(sqrt(14))/3
Find the zeros of -3x^2+4x-6=0
The zeros of -3x^2+4x-6=0 are x= 2/3-i(sqrt(14))/3 ,x= 2/3+i(sqrt(14))/3