What are the solutions to the equation x^2-3=2x ?

The solutions to the equation x^2-3=2x are x=3,x=-1

Find the zeros of x^2-3=2x

The zeros of x^2-3=2x are x=3,x=-1

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x^{2} - 3 = 2 x

x = 3, x = - 1

Solution steps

x^{2} - 3 = 2 x

Move

2 x

to the left side

x^{2} - 3 - 2 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} - 2 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot ( - 3 )}{2 \cdot 1}

(- 2)^{2} - 4 \cdot 1 \cdot (- 3) = 4

x_{1, 2} = \frac{- ( - 2 ) \pm 4}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 4}{2 \cdot 1}, x_{2} = \frac{- ( - 2 ) - 4}{2 \cdot 1}

x = \frac{- ( - 2 ) + 4}{2 \cdot 1} : 3

x = \frac{- ( - 2 ) - 4}{2 \cdot 1} : - 1

The solutions to the quadratic equation are:

x = 3, x = - 1

\frac{y + 4}{3} - 4 = 3 (2 y - 6) + 4

6 x^{3} + 4 x^{2} - 16 x

\frac{1}{8} + \frac{3}{5}

x^{2} - 55 = 26

3 a^{0}

What are the solutions to the equation x^2-3=2x ?
The solutions to the equation x^2-3=2x are x=3,x=-1
Find the zeros of x^2-3=2x
The zeros of x^2-3=2x are x=3,x=-1