What are the solutions to the equation -3=-1/4 (x-3)^2 ?

The solutions to the equation -3=-1/4 (x-3)^2 are x=2sqrt(3)+3,x=-2sqrt(3)+3

Find the zeros of -3=-1/4 (x-3)^2

The zeros of -3=-1/4 (x-3)^2 are x=2sqrt(3)+3,x=-2sqrt(3)+3

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- 3 = - \frac{1}{4} (x - 3)^{2}

x = 23 + 3, x = - 23 + 3

Decimal Notation

x = 6.46410 \dots, x = - 0.46410 \dots

Solution steps

- 3 = - \frac{1}{4} (x - 3)^{2}

Switch sides

- \frac{1}{4} (x - 3)^{2} = - 3

Multiply both sides by

- 4

(x - 3)^{2} = 12

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 3 = 12 : x = 23 + 3

Solve

x - 3 = - 12 : x = - 23 + 3

The solutions to the quadratic equation are:

x = 23 + 3, x = - 23 + 3

(x - 2)^{2} = 64

- 4 < \frac{4 x - 16}{8} < 2

15 = 9 x

x^{4} - 29 x^{2} + 100

- 7 p - 4 > 26 p - 94 - 7 p - 4 > 26 p - 94

What are the solutions to the equation -3=-1/4 (x-3)^2 ?
The solutions to the equation -3=-1/4 (x-3)^2 are x=2sqrt(3)+3,x=-2sqrt(3)+3
Find the zeros of -3=-1/4 (x-3)^2
The zeros of -3=-1/4 (x-3)^2 are x=2sqrt(3)+3,x=-2sqrt(3)+3