What are the solutions to the equation 6x(x+3)-4=16x-3 ?

The solutions to the equation 6x(x+3)-4=16x-3 are x=(-1+sqrt(7))/6 ,x=-(1+sqrt(7))/6

Find the zeros of 6x(x+3)-4=16x-3

The zeros of 6x(x+3)-4=16x-3 are x=(-1+sqrt(7))/6 ,x=-(1+sqrt(7))/6

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6 x (x + 3) - 4 = 16 x - 3

x = \frac{- 1 + 7}{6}, x = - \frac{1 + 7}{6}

Decimal Notation

x = 0.27429 \dots, x = - 0.60762 \dots

Solution steps

6 x (x + 3) - 4 = 16 x - 3

Expand

6 x (x + 3) - 4 : 6 x^{2} + 18 x - 4

6 x^{2} + 18 x - 4 = 16 x - 3

Move

3

to the left side

6 x^{2} + 18 x - 1 = 16 x

Move

16 x

to the left side

6 x^{2} + 2 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 6 ( - 1 )}{2 \cdot 6}

2^{2} - 4 \cdot 6 (- 1) = 27

x_{1, 2} = \frac{- 2 \pm 2 7}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- 2 + 2 7}{2 \cdot 6}, x_{2} = \frac{- 2 - 2 7}{2 \cdot 6}

x = \frac{- 2 + 2 7}{2 \cdot 6} : \frac{- 1 + 7}{6}

x = \frac{- 2 - 2 7}{2 \cdot 6} : - \frac{1 + 7}{6}

The solutions to the quadratic equation are:

x = \frac{- 1 + 7}{6}, x = - \frac{1 + 7}{6}

42 > 4 d + 6

7 (18) + 40

\frac{\frac{3}{4}}{3}

- \frac{1}{9} - \frac{2}{3}

3 (2 n - 6) = - 4 (n - 3)

What are the solutions to the equation 6x(x+3)-4=16x-3 ?
The solutions to the equation 6x(x+3)-4=16x-3 are x=(-1+sqrt(7))/6 ,x=-(1+sqrt(7))/6
Find the zeros of 6x(x+3)-4=16x-3
The zeros of 6x(x+3)-4=16x-3 are x=(-1+sqrt(7))/6 ,x=-(1+sqrt(7))/6