What is factor 4y^2+8y+3 ?

The solution to factor 4y^2+8y+3 is (2y+1)(2y+3)

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factor 4y^2+8y+3

factor

4 y^{2} + 8 y + 3

(2 y + 1) (2 y + 3)

Solution steps

4 y^{2} + 8 y + 3

Break the expression into groups

= (4 y^{2} + 2 y) + (6 y + 3)

Factor out

2 y

from

4 y^{2} + 2 y : 2 y (2 y + 1)

Factor out

3

from

6 y + 3 : 3 (2 y + 1)

= 2 y (2 y + 1) + 3 (2 y + 1)

Factor out common term

2 y + 1

= (2 y + 1) (2 y + 3)

3 x^{4} + 6 x^{3} - 3 x^{2} - 6 x

\frac{- 1}{( - 1 ) ^{2} + 1}

\frac{1}{2} (x + \frac{1}{3}) = \frac{5}{3}

h = 246536 \frac{1250 + 571}{1250 - 571}

y + 23 = 59