What are the solutions to the equation -2x^2+4x+3=0 ?

The solutions to the equation -2x^2+4x+3=0 are x=-(-2+sqrt(10))/2 ,x=(2+sqrt(10))/2

Find the zeros of -2x^2+4x+3=0

The zeros of -2x^2+4x+3=0 are x=-(-2+sqrt(10))/2 ,x=(2+sqrt(10))/2

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- 2 x^{2} + 4 x + 3 = 0

x = - \frac{- 2 + 10}{2}, x = \frac{2 + 10}{2}

Decimal Notation

x = - 0.58113 \dots, x = 2.58113 \dots

Solution steps

- 2 x^{2} + 4 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 ( - 2 ) \cdot 3}{2 ( - 2 )}

4^{2} - 4 (- 2) \cdot 3 = 210

x_{1, 2} = \frac{- 4 \pm 2 10}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 4 + 2 10}{2 ( - 2 )}, x_{2} = \frac{- 4 - 2 10}{2 ( - 2 )}

x = \frac{- 4 + 2 10}{2 ( - 2 )} : - \frac{- 2 + 10}{2}

x = \frac{- 4 - 2 10}{2 ( - 2 )} : \frac{2 + 10}{2}

The solutions to the quadratic equation are:

x = - \frac{- 2 + 10}{2}, x = \frac{2 + 10}{2}

\frac{( 3 k ^{2} ) ^{2}}{15 k ^{7}}

z^{2} - 10 z + 21

\frac{3 x}{8} + \frac{3 x}{4} = 9

(- \frac{11 x ^{2}}{2}) = 2900

What are the solutions to the equation -2x^2+4x+3=0 ?
The solutions to the equation -2x^2+4x+3=0 are x=-(-2+sqrt(10))/2 ,x=(2+sqrt(10))/2
Find the zeros of -2x^2+4x+3=0
The zeros of -2x^2+4x+3=0 are x=-(-2+sqrt(10))/2 ,x=(2+sqrt(10))/2