What are the solutions to the equation 3=x^2+2x ?

The solutions to the equation 3=x^2+2x are x=1,x=-3

Find the zeros of 3=x^2+2x

The zeros of 3=x^2+2x are x=1,x=-3

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3 = x^{2} + 2 x

x = 1, x = - 3

Solution steps

3 = x^{2} + 2 x

Switch sides

x^{2} + 2 x = 3

Move

3

to the left side

x^{2} + 2 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot ( - 3 )}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot (- 3) = 4

x_{1, 2} = \frac{- 2 \pm 4}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 2 + 4}{2 \cdot 1}, x_{2} = \frac{- 2 - 4}{2 \cdot 1}

x = \frac{- 2 + 4}{2 \cdot 1} : 1

x = \frac{- 2 - 4}{2 \cdot 1} : - 3

The solutions to the quadratic equation are:

x = 1, x = - 3

8 x y^{2} - 24 x y + 18 x

5^{\frac{1}{4}} \cdot 3^{\frac{1}{4}}

2 x^{2} + 8 x - 42

\frac{x - 1}{x + 1} - \frac{x}{x - 2} > 1

36000 = \frac{2 ( 9 \cdot 1 0 ^{9} ) ( \frac{x}{2.46} )}{0.217}

What are the solutions to the equation 3=x^2+2x ?
The solutions to the equation 3=x^2+2x are x=1,x=-3
Find the zeros of 3=x^2+2x
The zeros of 3=x^2+2x are x=1,x=-3