What are the solutions to the equation 40=490t^2 ?

The solutions to the equation 40=490t^2 are t= 2/7 ,t=-2/7

Find the zeros of 40=490t^2

The zeros of 40=490t^2 are t= 2/7 ,t=-2/7

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40 = 490 t^{2}

t = \frac{2}{7}, t = - \frac{2}{7}

Decimal Notation

t = 0.28571 \dots, t = - 0.28571 \dots

Solution steps

40 = 490 t^{2}

Switch sides

490 t^{2} = 40

Divide both sides by

490

t^{2} = \frac{4}{49}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

t = \frac{4}{49}, t = - \frac{4}{49}

\frac{4}{49} = \frac{2}{7}

- \frac{4}{49} = - \frac{2}{7}

t = \frac{2}{7}, t = - \frac{2}{7}

\frac{y}{4} = \frac{3}{6}

∣ 7 y + 6 ∣ - 5 = 0

3 x^{2} - 9 = - 201

r^{2} - 2 r + 6 = 0

2 x + 2 (x + 4) < 100

What are the solutions to the equation 40=490t^2 ?
The solutions to the equation 40=490t^2 are t= 2/7 ,t=-2/7
Find the zeros of 40=490t^2
The zeros of 40=490t^2 are t= 2/7 ,t=-2/7