What are the solutions to the equation 2x^2-12=0 ?

The solutions to the equation 2x^2-12=0 are x=sqrt(6),x=-sqrt(6)

Find the zeros of 2x^2-12=0

The zeros of 2x^2-12=0 are x=sqrt(6),x=-sqrt(6)

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2 x^{2} - 12 = 0

x = 6, x = - 6

Decimal Notation

x = 2.44948 \dots, x = - 2.44948 \dots

Solution steps

2 x^{2} - 12 = 0

Move

12

to the right side

2 x^{2} = 12

Divide both sides by

2

x^{2} = 6

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 6, x = - 6

2 \frac{16 n}{3}

\frac{x ^{\frac{1}{2}}}{x ^{3}}

450

9 s^{2} = 4

3 w^{3} - 2 w^{2} + 9 w - 6

What are the solutions to the equation 2x^2-12=0 ?
The solutions to the equation 2x^2-12=0 are x=sqrt(6),x=-sqrt(6)
Find the zeros of 2x^2-12=0
The zeros of 2x^2-12=0 are x=sqrt(6),x=-sqrt(6)