What are the solutions to the equation (2x+3)(3x-5)=0 ?

The solutions to the equation (2x+3)(3x-5)=0 are x=-3/2 ,x= 5/3

Find the zeros of (2x+3)(3x-5)=0

The zeros of (2x+3)(3x-5)=0 are x=-3/2 ,x= 5/3

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(2 x + 3) (3 x - 5) = 0

x = - \frac{3}{2}, x = \frac{5}{3}

Decimal Notation

x = - 1.5, x = 1.66666 \dots

Solution steps

(2 x + 3) (3 x - 5) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

2 x + 3 = 0 or 3 x - 5 = 0

Solve

2 x + 3 = 0 : x = - \frac{3}{2}

Solve

3 x - 5 = 0 : x = \frac{5}{3}

The solutions to the quadratic equation are:

x = - \frac{3}{2}, x = \frac{5}{3}

9147

\frac{2 x - 8}{10} - \frac{22 - x}{3} = 2

8 x^{4} - 10 x^{2} - 3

∣ x + 12 ∣ = ∣ 2 x + 6 ∣

(x + 1)^{2} = 0

What are the solutions to the equation (2x+3)(3x-5)=0 ?
The solutions to the equation (2x+3)(3x-5)=0 are x=-3/2 ,x= 5/3
Find the zeros of (2x+3)(3x-5)=0
The zeros of (2x+3)(3x-5)=0 are x=-3/2 ,x= 5/3