What are the solutions to the equation 8x^2+5x+6=0 ?

The solutions to the equation 8x^2+5x+6=0 are x=-5/16+i(sqrt(167))/(16),x=-5/16-i(sqrt(167))/(16)

Find the zeros of 8x^2+5x+6=0

The zeros of 8x^2+5x+6=0 are x=-5/16+i(sqrt(167))/(16),x=-5/16-i(sqrt(167))/(16)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

8 x^{2} + 5 x + 6 = 0

x = - \frac{5}{16} + i \frac{167}{16}, x = - \frac{5}{16} - i \frac{167}{16}

Solution steps

8 x^{2} + 5 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 8 \cdot 6}{2 \cdot 8}

Simplify

5^{2} - 4 \cdot 8 \cdot 6 : 167 i

x_{1, 2} = \frac{- 5 \pm 167 i}{2 \cdot 8}

Separate the solutions

x_{1} = \frac{- 5 + 167 i}{2 \cdot 8}, x_{2} = \frac{- 5 - 167 i}{2 \cdot 8}

x = \frac{- 5 + 167 i}{2 \cdot 8} : - \frac{5}{16} + i \frac{167}{16}

x = \frac{- 5 - 167 i}{2 \cdot 8} : - \frac{5}{16} - i \frac{167}{16}

The solutions to the quadratic equation are:

x = - \frac{5}{16} + i \frac{167}{16}, x = - \frac{5}{16} - i \frac{167}{16}

3 - 4 x (25 - 2 x) = 8 x^{2} + x - 300

7 \geq \frac{x + 3}{2} > 1

6 y^{2} + 17 y + 5

\frac{3}{4} (2 x + \frac{1}{2}) = 2

x + 6 = 3 - 2 x

What are the solutions to the equation 8x^2+5x+6=0 ?
The solutions to the equation 8x^2+5x+6=0 are x=-5/16+i(sqrt(167))/(16),x=-5/16-i(sqrt(167))/(16)
Find the zeros of 8x^2+5x+6=0
The zeros of 8x^2+5x+6=0 are x=-5/16+i(sqrt(167))/(16),x=-5/16-i(sqrt(167))/(16)