What are the solutions to the equation x^2-3x-3=0 ?

The solutions to the equation x^2-3x-3=0 are x=(3+sqrt(21))/2 ,x=(3-sqrt(21))/2

Find the zeros of x^2-3x-3=0

The zeros of x^2-3x-3=0 are x=(3+sqrt(21))/2 ,x=(3-sqrt(21))/2

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x^{2} - 3 x - 3 = 0

x = \frac{3 + 21}{2}, x = \frac{3 - 21}{2}

Decimal Notation

x = 3.79128 \dots, x = - 0.79128 \dots

Solution steps

x^{2} - 3 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 1 \cdot ( - 3 )}{2 \cdot 1}

(- 3)^{2} - 4 \cdot 1 \cdot (- 3) = 21

x_{1, 2} = \frac{- ( - 3 ) \pm 21}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 21}{2 \cdot 1}, x_{2} = \frac{- ( - 3 ) - 21}{2 \cdot 1}

x = \frac{- ( - 3 ) + 21}{2 \cdot 1} : \frac{3 + 21}{2}

x = \frac{- ( - 3 ) - 21}{2 \cdot 1} : \frac{3 - 21}{2}

The solutions to the quadratic equation are:

x = \frac{3 + 21}{2}, x = \frac{3 - 21}{2}

3 q \geq 9

10147

lo g_{2} (2)

x^{4} y + 8 x^{3} y - 6 x^{2} y^{2} - 48 x y^{2}

\frac{1}{2} x + 2 = 6

What are the solutions to the equation x^2-3x-3=0 ?
The solutions to the equation x^2-3x-3=0 are x=(3+sqrt(21))/2 ,x=(3-sqrt(21))/2
Find the zeros of x^2-3x-3=0
The zeros of x^2-3x-3=0 are x=(3+sqrt(21))/2 ,x=(3-sqrt(21))/2