What are the solutions to the equation 5x^2=2 ?

The solutions to the equation 5x^2=2 are x=sqrt(2/5),x=-sqrt(2/5)

Find the zeros of 5x^2=2

The zeros of 5x^2=2 are x=sqrt(2/5),x=-sqrt(2/5)

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5 x^{2} = 2

x = \frac{2}{5}, x = - \frac{2}{5}

Decimal Notation

x = 0.63245 \dots, x = - 0.63245 \dots

Solution steps

5 x^{2} = 2

Divide both sides by

5

x^{2} = \frac{2}{5}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{2}{5}, x = - \frac{2}{5}

72 - 2 y^{2}

(3 a)^{2}

\frac{∣ x + 1 ∣}{∣ x - 1 ∣} < 1

x^{2} - 12 x - 28 = 0

- 5 \leq \frac{x + 4}{2} < 1

What are the solutions to the equation 5x^2=2 ?
The solutions to the equation 5x^2=2 are x=sqrt(2/5),x=-sqrt(2/5)
Find the zeros of 5x^2=2
The zeros of 5x^2=2 are x=sqrt(2/5),x=-sqrt(2/5)