What is (1+9/(c-1))/(1-9/(c-1)) ?

The solution to (1+9/(c-1))/(1-9/(c-1)) is (c+8)/(c-10)

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simplify (1+9/(c-1))/(1-9/(c-1))

simplify

\frac{1 + \frac{9}{c - 1}}{1 - \frac{9}{c - 1}}

\frac{c + 8}{c - 10}

Solution steps

\frac{1 + \frac{9}{c - 1}}{1 - \frac{9}{c - 1}}

Join

1 + \frac{9}{c - 1} : \frac{c + 8}{c - 1}

= \frac{\frac{c + 8}{c - 1}}{1 - \frac{9}{c - 1}}

Join

1 - \frac{9}{c - 1} : \frac{c - 10}{c - 1}

= \frac{\frac{c + 8}{c - 1}}{\frac{c - 10}{c - 1}}

Apply the fraction rule:

\frac{\frac{a}{b}}{\frac{c}{d}} = \frac{a \cdot d}{b \cdot c}

= \frac{( c + 8 ) ( c - 1 )}{( c - 1 ) ( c - 10 )}

Cancel the common factor:

c - 1

= \frac{c + 8}{c - 10}

3 \cdot (\frac{1}{3})^{2}

(2 x + 1)^{2} = 0

(x^{- \frac{4}{7}})^{7}

v p + 96 + 12 v + 8 p

What is (1+9/(c-1))/(1-9/(c-1)) ?
The solution to (1+9/(c-1))/(1-9/(c-1)) is (c+8)/(c-10)