What are the solutions to the equation 7x^2+28=0 ?

The solutions to the equation 7x^2+28=0 are x=2i,x=-2i

Find the zeros of 7x^2+28=0

The zeros of 7x^2+28=0 are x=2i,x=-2i

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7 x^{2} + 28 = 0

x = 2 i, x = - 2 i

Solution steps

7 x^{2} + 28 = 0

Move

28

to the right side

7 x^{2} = - 28

Divide both sides by

7

x^{2} = - 4

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 4, x = - - 4

- 4 = 2 i

- - 4 = - 2 i

x = 2 i, x = - 2 i

\frac{k ^{14} + 4 k ^{7} + 3}{2 k ^{11} + 2 k ^{4}}

- x^{3} + 2 x^{2} + 13 x + 10 > 0

- 5 + 6 ∣ 2 x + 2 ∣ = 7

x + 4 = 5

\frac{ln ( \frac{1}{2} )}{1620}

What are the solutions to the equation 7x^2+28=0 ?
The solutions to the equation 7x^2+28=0 are x=2i,x=-2i
Find the zeros of 7x^2+28=0
The zeros of 7x^2+28=0 are x=2i,x=-2i