What is sqrt(x)<= 1 ?

The solution to sqrt(x)<= 1 is 0<= x<= 1

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sqrt(x)<= 1

x \leq 1

0 \leq x \leq 1

Interval Notation

[0, 1]

Solution steps

x \leq 1

Square both sides

(x)^{2} \leq 1^{2}

Simplify

x \leq 1

Find singularity points

Find non-negative values for radicals:

x \geq 0

Combine the intervals

x \leq 1 and x \geq 0

Merge Overlapping Intervals

0 \leq x \leq 1

1 - r = - 5

y^{2} + 5 y - 36

\frac{2}{3} - 2

28 x^{3} + 12 x^{2} - 112 x - 48

2 + 3 (x + 1) = 6 x