What is the answer to (x-4)/2-(3x+1)/3 =(2x-3)/4+(3x)/6 ?

The answer to (x-4)/2-(3x+1)/3 =(2x-3)/4+(3x)/6 is x=-19/18

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(x-4)/2-(3x+1)/3 =(2x-3)/4+(3x)/6

\frac{x - 4}{2} - \frac{3 x + 1}{3} = \frac{2 x - 3}{4} + \frac{3 x}{6}

x = - \frac{19}{18}

Decimal Notation

x = - 1.05555 \dots

Solution steps

\frac{x - 4}{2} - \frac{3 x + 1}{3} = \frac{2 x - 3}{4} + \frac{3 x}{6}

Cancel

\frac{3 x}{6} : \frac{x}{2}

\frac{x - 4}{2} - \frac{3 x + 1}{3} = \frac{2 x - 3}{4} + \frac{x}{2}

Multiply by LCM

6 (x - 4) - 4 (3 x + 1) = 3 (2 x - 3) + 6 x

Expand

6 (x - 4) - 4 (3 x + 1) : - 6 x - 28

Expand

3 (2 x - 3) + 6 x : 12 x - 9

- 6 x - 28 = 12 x - 9

Move

28

to the right side

- 6 x = 12 x + 19

Move

12 x

to the left side

- 18 x = 19

Divide both sides by

- 18

x = - \frac{19}{18}

\frac{x}{2} - \frac{x}{3} = x + 2

12 - ∣ x + 8 ∣ = 3

10 q^{3} r + 5 q^{3} + 20 q^{2} r + 10 q^{2}

x^{7} y^{7} \cdot 3 5 x^{3} y^{2}

\frac{x}{5} + 4 = \frac{x}{3}

What is the answer to (x-4)/2-(3x+1)/3 =(2x-3)/4+(3x)/6 ?
The answer to (x-4)/2-(3x+1)/3 =(2x-3)/4+(3x)/6 is x=-19/18
Solve for x: (x-4)/2-(3x+1)/3 =(2x-3)/4+(3x)/6
The solution is x=-19/18