What is the answer to (c+3)-2c-(1-3c)=2 ?

The answer to (c+3)-2c-(1-3c)=2 is c=0

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(c+3)-2c-(1-3c)=2

(c + 3) - 2 c - (1 - 3 c) = 2

c = 0

Solution steps

(c + 3) - 2 c - (1 - 3 c) = 2

Remove parentheses:

(a) = a

c + 3 - 2 c - (1 - 3 c) = 2

Group like terms

c - 2 c - (- 3 c + 1) + 3 = 2

Add similar elements:

c - 2 c = - c

- c - (- 3 c + 1) + 3 = 2

Move

3

to the right side

- c - (- 3 c + 1) = - 1

Expand

- c - (- 3 c + 1) : 2 c - 1

2 c - 1 = - 1

Move

1

to the right side

2 c = 0

Divide both sides by

2

c = 0

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What is the answer to (c+3)-2c-(1-3c)=2 ?
The answer to (c+3)-2c-(1-3c)=2 is c=0
Solve for c: (c+3)-2c-(1-3c)=2
The solution is c=0